1.4 – Density

IGCSE Physics  |  Core & Supplement

1. What is Density? #

Definition Density is the mass of a substance per unit volume. It tells you how much matter is packed into a given space.

The equation for density is:

$$\rho = \frac{m}{V}$$
  • $\rho$ (rho) = density ($\text{g/cm}^3$ or $\text{kg/m}^3$)
  • $m$ = mass ($\text{g}$ or $\text{kg}$)
  • $V$ = volume ($\text{cm}^3$ or $\text{m}^3$)

You can rearrange this formula to find mass or volume:

$$m = \rho \times V \qquad\qquad V = \frac{m}{\rho}$$
Reference value: The density of water is $1\ \text{g/cm}^3$ (or $1000\ \text{kg/m}^3$). This is a useful number to remember when comparing densities.
Worked Example — Finding volume using the rearranged formula

A piece of quartz has mass 200 g and density $2.5\ \text{g/cm}^3$. Find its volume.

  1. Formula: $$V = \frac{m}{\rho}$$
  2. Given: $m = 200\ \text{g}$, $\rho = 2.5\ \text{g/cm}^3$
  3. Express 2.5 as a fraction, then apply KCF (Keep, Change, Flip): $$V = 200 \div \frac{5}{2} = \frac{200}{1} \times \frac{2}{5}$$
  4. Cross-cancel — top-left 200 and bottom-right 5 share a factor of 5: $$V = \frac{\cancelto{40}{200}}{1} \times \frac{2}{\cancelto{1}{5}} = \frac{40 \times 2}{1 \times 1}$$
  5. Answer: $$V = 80\ \text{cm}^3$$

2. Measuring Density #

2a. Density of a Liquid #

  1. Place an empty measuring cylinder on a balance. Record its mass as $m_1$.
  2. Pour the liquid into the cylinder. Read the volume $V$ from the scale.
  3. Record the new mass of the cylinder + liquid as $m_2$.
  4. Mass of liquid: $m = m_2 – m_1$
  5. Calculate density: $\rho = \dfrac{m}{V}$
Worked Example — Density of a liquid

Empty cylinder mass = 80 g. Cylinder + liquid mass = 160 g. Volume of liquid = 50 cm³.

  1. Formula: $$\rho = \frac{m}{V}$$
  2. Given: $m = 160 – 80 = 80\ \text{g}$, $V = 50\ \text{cm}^3$
  3. Substitute: $$\rho = \frac{80}{50}$$
  4. Answer: $$\rho = 1.6\ \text{g/cm}^3$$

2b. Density of a Regularly Shaped Solid #

A regularly shaped solid has a shape with a known volume formula — for example a cube, rectangular block, or cylinder.

  1. Use a ruler (or vernier calipers) to measure the dimensions.
  2. Calculate the volume using the correct formula.
    For a rectangular block: $V = \text{length} \times \text{width} \times \text{height}$
  3. Use a balance to measure the mass.
  4. Calculate density: $\rho = \dfrac{m}{V}$
Worked Example — Density of a metal block

A metal cube has sides of 4 cm each. Its mass is 512 g.

  1. Formula: $$\rho = \frac{m}{V}$$
  2. Find volume: $$V = 4 \times 4 \times 4 = 64\ \text{cm}^3$$
  3. Given: $m = 512\ \text{g}$, $V = 64\ \text{cm}^3$
  4. Substitute: $$\rho = \frac{512}{64}$$
  5. Answer: $$\rho = 8\ \text{g/cm}^3$$

2c. Density of an Irregularly Shaped Solid (Volume by Displacement) #

An irregularly shaped solid (like a rock) has no simple formula for volume. We find its volume by measuring how much water it pushes aside — this is called volume by displacement.

  1. Use a balance to measure the mass of the solid.
  2. Fill a measuring cylinder with water. Record the initial volume $V_1$.
  3. Carefully lower the solid into the water (make sure it is fully submerged). Record the new volume $V_2$.
  4. Volume of solid: $V = V_2 – V_1$
  5. Calculate density: $\rho = \dfrac{m}{V}$
Important: The solid must sink completely in the water. This method only works for objects that are denser than water and sink to the bottom.
Worked Example — Density of a rock

A rock has mass 180 g. Water level before = 40 cm³. Water level after submerging the rock = 70 cm³.

  1. Formula: $$\rho = \frac{m}{V}$$
  2. Find volume: $$V = 70 – 40 = 30\ \text{cm}^3$$
  3. Given: $m = 180\ \text{g}$, $V = 30\ \text{cm}^3$
  4. Substitute: $$\rho = \frac{180}{30}$$
  5. Answer: $$\rho = 6\ \text{g/cm}^3$$

3. Floating and Sinking #

You can use density to predict whether an object will float or sink in a liquid.

Rule
  • Object density less than liquid density → object floats
  • Object density greater than liquid density → object sinks
  • Object density equal to liquid density → object stays suspended (does not float or sink)
In water ($\rho = 1\ \text{g/cm}^3$): Any object with density less than $1\ \text{g/cm}^3$ floats. Any object with density greater than $1\ \text{g/cm}^3$ sinks.
Worked Example — Will it float or sink in water?

Water density = $1.0\ \text{g/cm}^3$

Object Density (g/cm³) Comparison Result
Wood block 0.6 $0.6 < 1.0$ Floats
Ice 0.92 $0.92 < 1.0$ Floats
Steel bolt 7.8 $7.8 > 1.0$ Sinks

4. Liquids Floating on Other Liquids Supplement #

When two liquids that do not mix are placed together, the less dense liquid rises to the top and the more dense liquid sinks to the bottom.

Rule
  • Lower density liquid → floats on top
  • Higher density liquid → sinks to the bottom
Worked Example — Oil and water

Vegetable oil has density $0.9\ \text{g/cm}^3$. Water has density $1.0\ \text{g/cm}^3$. They do not mix.

Since $0.9 < 1.0$, the oil has a lower density than water.

Conclusion: The oil floats on top of the water.

Syllabus Reference — 1.4 Density #

Core

  1. Define density as mass per unit volume; recall and use the equation $\rho = \dfrac{m}{V}$
  2. Describe how to determine the density of a liquid, of a regularly shaped solid and of an irregularly shaped solid which sinks in a liquid (volume by displacement), including appropriate calculations
  3. Determine whether an object floats based on density data

Supplement

  1. Determine whether one liquid will float on another liquid based on density data given that the liquids do not mix

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