- The cyclist traveled at constant speed between 2-6 seconds (this is shown by the horizontal line segment)
- The maximum speed was 10 m/s (shown on the y-axis where the horizontal line segment is)
- a) Speeding up
- Explanation: The line goes up from 0 to 10 m/s, showing acceleration/speeding up
- Between 6-8 seconds, the cyclist was slowing down (decelerating), shown by the downward slope back to 0 m/s
- The cyclist maintained their top speed of 10 m/s for 4 seconds (from t=2s to t=6s)
- Total distance calculation:
- First section (0-2s): Triangle = ½ × 2s × 10m/s = 10m
- Middle section (2-6s): Rectangle = 4s × 10m/s = 40m
- Last section (6-8s): Triangle = ½ × 2s × 10m/s = 10m Total distance = 10 + 40 + 10 = 60 meters
- b) 2-4 seconds
- Explanation: During this time the cyclist maintained their highest speed (10 m/s) for the full 2 seconds, covering 20 meters. All other 2-second intervals either involved acceleration, deceleration, or lower speeds.
- Distance between 2-6 seconds = 40 meters
- Calculation: Area of rectangle = speed × time = 10 m/s × 4s = 40m
Answers – Velocity Time Graphs – 2
Powered by BetterDocs