Answers – 6.1 – Photosynthesis

IGCSE Biology  |  Practice Test — Answers & Worked Solutions

Section A — Recall
Questions 1–10
1.

Write down the definition of photosynthesis.

Answer
Photosynthesis is the process by which plants make carbohydrates from carbon dioxide and water, using light energy.
Exam tip: Three parts are needed for full marks — (1) plants make carbohydrates, (2) the raw materials are CO2 and water, (3) using light energy. Missing any one of these loses a mark.
2.

What is chlorophyll? State where it is found in plant cells.

Answer
Chlorophyll is a green pigment found inside chloroplasts in plant cells.
Exam tip: Three key words must appear: “green”, “pigment”, and “chloroplasts”. Writing “found in leaves” is not precise enough — it must be chloroplasts.
3.

State what chlorophyll does with light energy during photosynthesis.

Answer
Chlorophyll absorbs light energy and converts it into chemical energy, which is stored in glucose and other carbohydrates.
4.

Write the word equation for photosynthesis.

Answer
carbon dioxide  +  water  →  glucose  +  oxygen
(using light energy and chlorophyll)
5.

Write the balanced chemical equation for photosynthesis.

Answer
$$6\text{CO}_2 \;+\; 6\text{H}_2\text{O} \;\xrightarrow{\text{light, chlorophyll}}\; \text{C}_6\text{H}_{12}\text{O}_6 \;+\; 6\text{O}_2$$
Remember the numbers: 6 CO2, 6 H2O, 1 C6H12O6, 6 O2. You can check the equation is balanced: both sides have 6 carbon, 12 hydrogen, and 18 oxygen atoms.
6.

Name the carbohydrate that plants use to build their cell walls.

Answer
Cellulose
7.

State one use of sucrose in plants.

Answer
Sucrose is transported through the plant to carry energy from the leaves to other parts of the plant.
8.

State what is meant by a limiting factor in photosynthesis.

Answer
A limiting factor is the factor in shortest supply that is preventing the rate of photosynthesis from increasing further.
Exam tip: The key phrase is “preventing the rate from increasing further”. A limiting factor does not stop photosynthesis — it just stops it from going faster.
9.

Name three factors that can limit the rate of photosynthesis.

Answer
1. Light intensity    2. Carbon dioxide concentration    3. Temperature
10.

Before testing a leaf for starch, a plant must be destarched first. Why is this step necessary?

Answer

The plant is kept in the dark for 24–48 hours. During this time, it uses up all the starch already stored in its leaves.

This ensures that any starch found in the leaf after the experiment was made during the test, not stored beforehand. Without destarching, the results would be unreliable.
Section B — Application
Questions 11–20
11.

A variegated leaf has green patches and white patches. After being left in bright light for several hours, the whole leaf is tested with iodine solution.

(a) Predict the colour of the iodine on the green patches. Explain your answer.

(b) Predict the colour of the iodine on the white patches. Explain your answer.

Answer
(a) Green patches
Blue-black. The green patches contain chlorophyll, so photosynthesis can occur. The plant has made starch, which turns iodine blue-black.
(b) White patches
Orange-brown. The white patches contain no chlorophyll, so photosynthesis cannot occur. No starch has been made, so the iodine stays orange-brown.
Exam tip: You must state the colour AND explain using the word “chlorophyll”. Stating the colour alone is not enough for full marks.
12.

A well-destarched leaf is partially covered with black foil and left in bright light for several hours. When tested with iodine, only the uncovered part turns blue-black.

State the conclusion you can draw from this result.

Answer
Light is needed for photosynthesis.

The covered part received no light and produced no starch — photosynthesis did not occur. The uncovered part received light, photosynthesised, and stored starch. Since the only difference between the two parts was light, we can conclude that light is required for photosynthesis.

13.

A well-destarched plant is placed in a sealed transparent container along with soda lime, which absorbs all the CO2 from the air. The container is left in bright light for 24 hours. A leaf is then removed and tested with iodine.

(a) What result would you expect from the iodine test?

(b) Explain why this result is expected.

Answer
(a) Expected result
The leaf stays orange-brown — no starch is present.
(b) Explanation

Soda lime removed all the CO2 from the air inside the container. CO2 is a raw material for photosynthesis. Without it, the plant cannot carry out photosynthesis, so no glucose is produced and no starch is stored in the leaf.

Conclusion: Carbon dioxide is needed for photosynthesis.
14.

A student places a piece of Elodea (a water plant) near a lamp. She counts 10 oxygen bubbles per minute. She then moves the lamp further away from the plant.

(a) Predict what will happen to the number of bubbles per minute.

(b) Explain your prediction.

Answer
(a) Prediction
The number of bubbles per minute will decrease.
(b) Explanation

Moving the lamp further away reduces the light intensity reaching the plant. With less light energy available, the rate of photosynthesis decreases. Less oxygen is produced, so fewer bubbles are released per minute.

15.

Explain why plants store excess glucose as starch rather than keeping it as glucose inside cells.

Answer

Starch is insoluble — it does not dissolve in the water inside cells. This means it does not affect the water balance (osmosis) of the cell.

Glucose is soluble. If glucose accumulated in the cell, it would affect the water balance inside the cell, which could disrupt normal cell function.

Storing energy as insoluble starch prevents any effect on the cell’s water balance and is a stable form of storage.
16.

A plant at 5°C photosynthesises more slowly than an identical plant at 25°C, even when both have the same light intensity and CO2 concentration. Explain why.

Answer

Photosynthesis is controlled by enzymes. At 5°C, there is very little kinetic energy, so enzyme molecules and their substrates collide less frequently and less successfully. The enzymes work much more slowly.

At 25°C, the temperature is closer to the enzymes’ optimum. There is more kinetic energy, more successful collisions occur, and the enzymes work faster.

The higher temperature at 25°C increases enzyme activity, which increases the rate of photosynthesis.
17.

The rate of photosynthesis in a plant increases as CO2 concentration rises from 0.01% to 0.04%. When CO2 rises further from 0.04% to 0.08%, the rate stays the same. Explain why the rate stops increasing.

Answer

When CO2 rises above 0.04%, CO2 is no longer the limiting factor. Another factor — either light intensity or temperature — has now become limiting.

Even though CO2 is plentiful, the plant cannot photosynthesise faster because the other limiting factor is holding back the rate. The rate can only increase when that limiting factor is also improved.
18.

Hydrogencarbonate indicator (starting colour: orange-red) is added to two sealed test tubes, each containing a piece of Elodea. Tube A is placed in bright light. Tube B is covered with foil to block all light. After one hour:

(a) State the expected colour of the indicator in Tube A and explain why.

(b) State the expected colour of the indicator in Tube B and explain why.

Answer
(a) Tube A — in light
Colour: Purple / magenta

The plant photosynthesises in the light, absorbing CO2 from the water in the tube. As CO2 decreases, the solution becomes more alkaline, causing the indicator to turn purple.

(b) Tube B — in dark
Colour: Yellow

In the dark, the plant cannot photosynthesise, but it continues to respire. Respiration releases CO2 into the water. As CO2 increases, the solution becomes more acidic, causing the indicator to turn yellow.

Colour summary: Orange/red = normal CO2 (starting point)  |  Yellow = more CO2 (acidic)  |  Purple = less CO2 (alkaline)
19.

A greenhouse farmer wants to increase the rate of photosynthesis in his tomato plants during winter. Suggest two changes he could make and explain why each would help.

Answer
Change 1 — Increase light intensity

Install artificial lighting in the greenhouse. Light provides the energy for photosynthesis. More light means more energy is available for chlorophyll to absorb, so the rate of photosynthesis increases.

Change 2 — Increase CO2 concentration

Inject extra CO2 into the greenhouse. CO2 is a raw material for photosynthesis. More CO2 available means the reaction can proceed faster, increasing the rate.

Also acceptable: Raise the temperature (up to the optimum, ~25°C) — this speeds up the enzyme-controlled reactions of photosynthesis.
20.

A student says: “If I give a plant more light, the rate of photosynthesis will always increase.” Explain why this statement is not always correct.

Answer

More light will only increase the rate if light is the limiting factor. If CO2 concentration or temperature is already the limiting factor, adding more light will have no effect — the rate is being held back by something else.

The rate can only increase when you improve the actual limiting factor. If light is not the factor in shortest supply, increasing it makes no difference.
Section C — Challenge
Questions 21–25
21.

Photosynthesis produces glucose, which the plant converts into other useful substances.

(a) Name the two raw materials needed for photosynthesis.

(b) State where each raw material enters the plant.

(c) Name the two products of photosynthesis.

(d) For each carbohydrate below, state one use in the plant: Starch, Cellulose, Sucrose.

Answer
(a) Raw materials
Carbon dioxide and water.
(b) Where they enter

Carbon dioxide enters through the stomata — small pores on the surface of leaves.

Water is absorbed through the roots.

(c) Products
Glucose and oxygen.
(d) Uses of carbohydrates

Starch — stored as an energy store in cells (it is insoluble, so it does not affect osmosis).

Cellulose — used to build plant cell walls, giving the plant structure and strength.

Sucrose — transported through the plant via the phloem to carry energy to other parts.

Note: Glucose itself is used directly in respiration to release energy for the plant’s own life processes.
22.

A student investigates the effect of temperature on the rate of photosynthesis using Elodea. She counts oxygen bubbles per minute at different temperatures, keeping light intensity and CO2 concentration constant.

Temperature (°C)Bubbles per minute
105
2012
3019
408
501

(a) Describe the trend between 10°C and 30°C.

(b) Explain what is happening at 40°C and 50°C.

(c) State what the student is measuring and explain why counting oxygen bubbles is a suitable method.

Answer
(a) Trend between 10°C and 30°C

As temperature increases from 10°C to 30°C, the rate of photosynthesis increases — the number of bubbles rises from 5 to 19 per minute. Higher temperatures give enzyme molecules more kinetic energy, increasing the frequency of successful collisions and speeding up the reaction.

(b) At 40°C and 50°C

Above the optimum temperature (~30°C), the rate drops sharply. The high temperature causes the enzymes controlling photosynthesis to denature — they lose their three-dimensional shape and can no longer function. At 50°C, nearly all enzymes have denatured and the rate is almost zero.

Enzyme denaturation (not just slowing down) is the reason for the sharp drop — the enzymes are permanently damaged, not just inactive.
(c) What is being measured

The student is measuring the rate of oxygen production (bubbles per minute). This is a suitable method because oxygen is a direct product of photosynthesis — more bubbles per minute means photosynthesis is occurring faster.

IMAGE NEEDED: Graph showing rate of photosynthesis (y-axis) vs temperature (x-axis) — curve rises to a peak around 30°C then falls sharply

Google Images Search: “IGCSE biology rate of photosynthesis temperature graph labeled educational”

23.

A student designs an experiment to show that carbon dioxide is needed for photosynthesis.

(a) Describe how the experiment should be set up, including what acts as the control.

(b) State how you would test for the product of photosynthesis and describe the expected results.

(c) Name one variable the student must keep constant and explain why.

Answer
(a) Experimental setup
  1. Take two plants of the same type and size. Destarch both by keeping them in the dark for 24–48 hours.
  2. Experimental plant: Place in a sealed transparent container with soda lime (which absorbs all CO2 from the air).
  3. Control plant: Place in an identical sealed transparent container without soda lime. This plant has normal CO2 levels.
  4. Leave both containers in the same bright light at the same temperature for 24 hours.
The only difference between the two setups is the presence of CO2. Everything else is identical.
(b) Testing and expected results

Remove a leaf from each plant and test both with iodine solution.

Experimental plant (soda lime, no CO2): Leaf stays orange-brown — no starch, because photosynthesis could not occur without CO2.

Control plant (normal CO2): Leaf turns blue-black — starch is present, because photosynthesis occurred.

(c) Variable to control

Any one of the following (with explanation):

Light intensity — must be the same for both plants. Different light levels would change the rate of photosynthesis, making it impossible to conclude that the result was caused by CO2 alone.

Temperature — must be the same. Temperature affects enzyme activity; if different, results could be due to temperature, not CO2.

Exam tip: In a valid controlled experiment, only ONE variable changes (CO2 in this case). All other variables must be kept constant.
24.

A plant is given increasing light intensity while CO2 concentration and temperature are kept constant.

(a) Define the term limiting factor.

(b) Describe and explain what happens to the rate of photosynthesis as light intensity increases from very low to very high.

(c) The rate eventually stops increasing even though light intensity is still rising. Name one factor that may now be limiting the rate, and explain how increasing it would help.

Answer
(a) Definition
A limiting factor is the factor in shortest supply that is preventing the rate of photosynthesis from increasing further.
(b) Effect of increasing light intensity

At very low light intensity: The rate of photosynthesis is low. Light is the limiting factor — there is not enough energy for chlorophyll to absorb, so the reaction proceeds slowly.

As light intensity increases: More energy becomes available. The rate of photosynthesis rises — the graph increases steeply.

At high light intensity: The rate levels off and stops increasing. Light is no longer the limiting factor. Another factor — CO2 or temperature — is now in shortest supply and is holding back the rate.

The graph rises steeply at first, then flattens into a plateau when a different factor becomes limiting.
(c) New limiting factor

Carbon dioxide concentration: If CO2 is now limiting, increasing the CO2 supply gives the plant more raw material. The rate of photosynthesis can then increase again.

OR Temperature: If temperature is limiting, increasing it (up to the optimum) speeds up enzyme activity, allowing the rate to rise further.

25.

A student wants to show that light is needed for photosynthesis using the starch test.

(a) Why must the plant be destarched before starting the experiment?

(b) Describe the experimental setup, including what acts as the control.

(c) State the expected result for the experimental leaf (no light) and the control leaf (in light).

(d) A second student forgets to destarch her plant before starting. Explain why this makes her results unreliable.

Answer
(a) Why destarch first

If the plant is not destarched, it already contains starch from before the experiment. Any starch found after the test could have been there already, not newly made during the experiment.

Destarching gives a fair starting point — any starch found afterwards must have been made during the experiment.
(b) Experimental setup
  1. Keep the plant in the dark for 24–48 hours to destarch it.
  2. Cover part of one leaf tightly with black foil to block all light. This is the experimental part (no light).
  3. Leave the rest of the same leaf (or another leaf on the same plant) uncovered. This is the control — it receives normal light.
  4. Leave the plant in bright light for several hours, then remove the leaf and test both parts with iodine solution.
Using the same leaf (or same plant) for both parts ensures all other variables — chlorophyll, CO2, temperature — are identical. The only difference is light.
(c) Expected results

Experimental leaf (covered, no light): Orange-brown — no starch. Photosynthesis could not occur without light.

Control leaf (uncovered, in light): Blue-black — starch present. Photosynthesis occurred and starch was stored.

(d) Why forgetting to destarch makes results unreliable

If the plant was not destarched, both the covered and uncovered parts already contain starch. After the experiment, both parts would test blue-black — even the covered part that received no light.

It becomes impossible to tell whether the starch was made during the experiment or was stored beforehand. No valid conclusion can be drawn about whether light is needed for photosynthesis.
Exam tip: Destarching is essential for all three photosynthesis experiments — testing the need for light, chlorophyll, and carbon dioxide. Always mention it as the first step in any experimental setup.

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