IGCSE Mathematics | Core Topic
1. Rounding to Decimal Places #
Decimal places (d.p.) are the digits that come after the decimal point. Rounding to a certain number of decimal places means keeping only that many digits after the point.
- If it is 5 or more → round up (increase the last kept digit by 1)
- If it is 4 or less → round down (keep the last kept digit the same)
- We want 2 d.p., so we keep two digits after the point: 7 and 4
- Look at the next digit: 6 → 6 is 5 or more, so round up
- The 4 becomes 5. Answer: $3.746 \approx 3.75$
- We keep two digits after the point: 9 and 9
- Look at the next digit: 5 → 5 or more, so round up
- The second 9 rounds up to 10, which carries over: $12.99 \rightarrow 13.00$
- Answer: $12.995 \approx 13.00$
2. Rounding to Significant Figures #
Significant figures (s.f.) count from the first non-zero digit of the number. This method works for both large and small numbers.
- Start counting from the first non-zero digit
- Every digit after that counts — including zeros that sit between non-zero digits
- Leading zeros (zeros before the first non-zero digit) do not count
IMAGE NEEDED: Diagram labelling significant figures in a number like 0.00304 — showing which zeros count and which do not
Google Images Search: “significant figures counting rules diagram IGCSE maths educational”
Rounding large numbers #
- The first significant figure is 5 (the thousands digit)
- Look at the next digit: 7 → 7 is 5 or more, so round up
- Replace the remaining digits with zeros: $5764 \approx 6000$
- The first two significant figures are 5 and 7
- Look at the next digit: 6 → 6 is 5 or more, so round up
- The 7 becomes 8. Replace the rest with zeros: $5764 \approx 5800$
Rounding small decimal numbers #
- The leading zeros do not count. The first significant figure is 4
- The second significant figure is 3
- Look at the next digit: 6 → 6 is 5 or more, so round up
- The 3 becomes 4: $0.004\,362 \approx 0.0044$
3. Estimation #
Estimation means finding an approximate answer quickly, without a calculator. It is very useful for checking whether your calculator answer looks reasonable.
- Round each number in the calculation to 1 significant figure
- Carry out the simplified calculation by hand
- Write the answer using the $\approx$ symbol (means “approximately equal to”)
- Round each number to 1 s.f.:
- $41.3 \approx 40$
- $9.79 \approx 10$
- $0.765 \approx 0.8$
- Substitute into the calculation: $$\frac{40}{10 \times 0.8} = \frac{40}{8} = 5$$
- The estimated answer is $\approx 5$
- Round each number to 1 s.f.:
- $318 \approx 300$
- $5.12 \approx 5$
- $0.491 \approx 0.5$
- Substitute and calculate: $$\frac{300 \times 5}{0.5} = \frac{1500}{0.5} = 3000$$
- The estimated answer is $\approx 3000$
4. Rounding to a Reasonable Degree of Accuracy #
In real problems, you must choose a sensible level of accuracy. The context of the problem tells you how precise your answer should be.
| Context | Reasonable accuracy | Example |
|---|---|---|
| Money | 2 decimal places | \$14.57 |
| Long distances | Nearest km or whole number | 240 km |
| Short lengths | Nearest mm or cm | 3.4 cm |
| Time | Nearest minute or second | 45 minutes |
| Large populations or counts | Nearest thousand or 3 s.f. | 2 400 000 |
A rectangle has length $8.3\text{ cm}$ and width $4.7\text{ cm}$ (both given to 1 d.p.).
Area $= 8.3 \times 4.7 = 39.01\text{ cm}^2$
Since the original measurements were given to 1 d.p., a reasonable answer is:
Area $\approx 39.0\text{ cm}^2$ (1 d.p.)
Giving the answer as $39.01\text{ cm}^2$ would suggest more precision than the measurements actually have.
Syllabus Reference — C1.9 Estimation #
- Round values to a specified degree of accuracy. Includes decimal places and significant figures.
- Make estimates for calculations involving numbers, quantities and measurements.
- Round answers to a reasonable degree of accuracy in the context of a given problem.
